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8+9x-3x^2=0
a = -3; b = 9; c = +8;
Δ = b2-4ac
Δ = 92-4·(-3)·8
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{177}}{2*-3}=\frac{-9-\sqrt{177}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{177}}{2*-3}=\frac{-9+\sqrt{177}}{-6} $
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